N2H2 reduces IO3^(-) //H^+ .........

`N_2H_2` reduces `IO_3^(-) //H^+` ......

A

to `I^(+)`

B

with `I_2` as an intermediate by violet colour in `"CCl"_4` layer

C

to `I^(-)`

D

indicated by blue colour with starch

Verified by Experts

The correct Answer is:

A, B, D

`3N_(2)H_(4)+2IO_(3)^(-) rarr 3N_(2)+2I^(Theta)+6H_(2)O`

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