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In the oxidation of N(2)H(4) " to "N2 ...

In the oxidation of `N_(2)H_(4) " to "N_2` equivalent weight of `N_(2)H_(4)` would be........

Text Solution

Verified by Experts

The correct Answer is:
8
`overset(2xx2)(N_(2)H_4)rarroverset(2xx2)(N_(2))+4e^(-)`
Equivalent weight = `{:(" "GMW),(bar"change in oxidation "),(" state for one"),(" formula unit"):}=cancel(32)/cancel(4)=8, :. "Eq. wt of "N_(2)H_(4)=8` `
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