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PCl(5) in solid state exists as PCl(4)^(...

`PCl_(5)` in solid state exists as `PCl_(4)^(+) and PCl_(6)^(-)` and also in some solvents it undergoes dissociation as `2PCl_(5) hArr PCl_(4)^(+) +PCl_(6)^(-)`
The geometry and hydridisation of `PCl_(4)^(+)` is

A

Tetrahderal , `sp^3`

B

Octahedral , `sp^(3) d^(2)`

C

Linear , sp

D

Angular , `sp^2`

Text Solution

Verified by Experts

The correct Answer is:
A
`[PCl_4]^(+)` - No of Hybrid orbitals `=1/2 [5+4-1]=4`
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