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PCl(5) in solid state exists as PCl(4)^(...

`PCl_(5)` in solid state exists as `PCl_(4)^(+) and PCl_(6)^(-)` and also in some solvents it undergoes dissociation as `2PCl_(5) hArr PCl_(4)^(+) +PCl_(6)^(-)`
The geometry and hybridisation of `PCl_(6)^(-)` is

A

Octahedral , `sp^3`

B

Octahedral , `sp^3d^2`

C

Trigonal bipyramid `sp^3d`

D

See - saw , `sp^3 d `

Text Solution

Verified by Experts

The correct Answer is:
A
`[PCl_3]^(-)` - No. of Hybride orbitals `=1/2 [5+6-1]=6`
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