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The F2 liberated at the anode in the why...

The `F_2` liberated at the anode in the whytlaw Gray method is passed through U - tube, then the following reaction takes place 

A

`NaHF_(2) rarr NaF + HF`

B

`NaF + HF rarr NaHF_(2)`

C

`KH F_(2) rarr HF + KF`

D

`2F^(-1) - 2e^(-) rarr F_(2)`

Text Solution

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The correct Answer is:
B
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