Home
Class 12
CHEMISTRY
KMnO(4) is prepared by...

`KMnO_(4)` is prepared by

A

passing `Cl_(2)` through `K_(2)MnO_(4)` SOLUTION

B

passing `O_(2)` through `K_(2) MnO_(4)` solution

C

reaction of KOH with `KMnO_(4)`

D

Fusion of KOH with `MnO_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Passing `Cl_(2) ` through `K_(2) MnO_(4)` solution.
Promotional Banner

Similar Questions

Explore conceptually related problems

Molecular weight of KMnO_(4) is "M". In a reaction KMnO_(4) is reduced to KMnO_(4) . The equivalent weight of KMnO, is

In the reactant of KMnO_(4) with an oxalate in acidic medium. MnO_(4)^(-) is reduced to Mn^(2+) and C_(2)O_(4)^(2-) is oxidised to CO_(2) . Hence, 50 ml of 0.02 M KMnO_(4) is equivalent to

A sample of H_(2)O_(2) is x % by mass. If x ml of KMnO_(4) are required to oxidize 1 gm of this H_(2)O_(2) sample, calculate the normality of KMnO_(4) solution.

KMnO_4 acts as an oxidising agent in alkaline medium, when alkaline KMnO_4 is treated with KI, iodine ion is oxidised to

How many moles of KMnO_(4) are required to oxidise one mole of ferrous oxalate in acidic medium ?

How many moles of KMnO_(4) are required to liberate one gram mole of oxygen from H_(2)O_(2) in acid medium ?

KMnO_(4) is powerful oxidant where it converts into

Molecular weight of KMnO_4 is "M". In a reaction KMnO_4 is reduced to K_2MnO_4 . The equivalent weight of KMnO_4 is