Maximum percentage of available Cl(2) as...

Maximum percentage of available `Cl_(2)` as per formula `CaOCl_(2). H_(2)O` is x `xx` 7. Where the value of 'x' ?

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The correct Answer is:

7

`underset( 145 g m)(CaOCl_(2).H_(2)O) rarr underset( 71 g m ) ( Cl_(2)) , ` Valu of x `xx 7 = 49.` `:. x = ( 49)/( 7) = 7`

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