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NH(3) reacts with Cl(2) to give N(2) gas...

`NH_(3)` reacts with `Cl_(2)` to give `N_(2)` gas . How many number of moles of `Cl_(2)` are required ?

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The correct Answer is:
3
`2NH_(3) + 3Cl_(2) rarr N_(2) + 6 HCl`. No of moles of `Cl_(2)` required in .3..
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