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A 500g tooth paste sample has 0.2g fluor...

A 500g tooth paste sample has 0.2g fluoride concentration. The concentration of `F^(-)` ion in terms of ppm level is 100 `xx` X. What is the value of X ?

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Mass of solute = 0.2 gm in 500gm tooth paste. So concentration per kg `= ( 0.2) / ( 500) xx 100` gm `= 0.4 g m // kg `
Since to find the level of `F^(-) `ion in ppm we need to convert the conc. In Mg AS
Conc of `F^(-)` ion in `Mg //Kg = 0.4 xx 100 mg // g m = 400 mg // kg `
Hence level of `F^(-)` ion in ppm `= ( " weight of solute")/("weigth of ion") = 400 mg //kg = 400 p p m = 100 xx 4 ` p p m
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