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The bond order of Cl-O in ClO(4)^(-) is ...

The bond order of `Cl-O` in `ClO_(4)^(-)` is `(x)/( y )` then `x-y=?`

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The correct Answer is:
3
`:. (x)/( y ) = ( 7 )/( 4) , x - y = 7-4 = 3`
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