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The number of alpha particle in the nucl...

The number of `alpha` particle in the nuclear reaction `""_(90)^(238) Th to ""_(81)^(212) Bi` are : ____

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The correct Answer is:
4
`""_(92) Th^(228) to ""_(83) Bi^(212) + a (""_(2)He^(4)) + b (""_(-1) beta^(0)) , a = ((228 - 212)/(4)) = (16)/(4) = 4 alpha , b = ?`
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