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For the cell Zn// Zn^(2+) // // Cu^(2+) ...

For the cell `Zn// Zn^(2+) // // Cu^(2+) // Cu` , if the concentration of `Zn^(2+) and Cu^(2+)` ions is doubled , the emf of the cell

A

doubles

B

reduces to half

C

remains same

D

remains zero

Text Solution

Verified by Experts

The correct Answer is:
C
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