Home
Class 12
CHEMISTRY
The current strength required to displac...

The current strength required to displace 0.1 g. of `H_2` in 10 sec is

A

9.65 amp

B

1.988 amp

C

198 amp

D

965 amp

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise LEVEL-II (LECTURE SHEET ( EXERCISE -I ( SINGLE & ONE OR MORE THAN ONE CORRECT ANSWER )))|32 Videos
  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise LEVEL-II (LECTURE SHEET ( EXERCISE -II (LINKED COMPREHENSION TYPE QUESTIONS )) )|12 Videos
  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise LEVEL-I ( EXERCISE-I)|146 Videos
  • DILUTE SOLUTIONS

    AAKASH SERIES|Exercise EXERCISE - 1.2|55 Videos
  • ELEMENTS OF D - BLOCK

    AAKASH SERIES|Exercise EXERCISE - 5.2|33 Videos

Similar Questions

Explore conceptually related problems

When a current strength of 965 amp can deposit 0.9g of At metal in 20 sec. What is the efficiency of electrolysis ?

Calculate the current in amperes required to liberate 10g of silver electrolytically in 2 hrs from AgNO_(3) solution.

An electrolytic cell is constructed for preparing hydrogen. For the average current of 1 ampere in the circuit, the time required for producing 112 ml of H_2 at STP is approximately

H_(2)O_(2) acts both as oxidant and reductant. H_(2)O and O_(2) are products when H_(2)O_(2) acts as oxidant and reductant respectively. The strength of H_(2)O_(2) is expressed in terms of molarity, normality, % strength and volume strength. H_(2)O_(2) decomposes as H_(2)O_(2)rarrH_(2)+1//2O_(2)(g) i.e., one mole O_(2) is released from 2 mole H_(2)O_(2) .x. .volume. strength of H_(2)O_(2) means 1 volume (mL or litre) of H_(2)O_(2) sample released x volume (mL or litre) O_(2) gas at NTP on its decomposition. Hence molarity = x//11.2 moles per litre, i.e., normality of H_(2)O_(2)=x//5.6 Thus volume strength, i.e., x=5.6xx Normality. Weigth of H_(2)O_(2) (in gm) present in 100 mL H_(2)O_(2) solution is called percentage strength of H_(2)O_(2) How much volume of H_(2)O_(2) solution of 22.4 .vol. strength is required to oxidise 6.3 gm oxalic acid

The number of moles of H_(2) which is required to produce 10 moles of NH_(3) in the following reaction is aH_(2)(g)+bNO_(2)(g)tocNH_(3)(g)+dH_(2)O(g)

The volume strength of 1.5 N H_2O_2 is

AAKASH SERIES-ELECTROCHEMISTRY -LEVEL-I ( EXERCISE-II)
  1. The electrochemical equivalent of a metal is "y"g. "coulomb"^(-1). The...

    Text Solution

    |

  2. The electro chemical equivalent of an element is 0.0006735 g/C. Its eq...

    Text Solution

    |

  3. The current strength required to displace 0.1 g. of H2 in 10 sec is

    Text Solution

    |

  4. On electrolysing a sample of acidified water, 22.4 ml of hydrogen was ...

    Text Solution

    |

  5. An electrolytic cell is constructed for preparing hydrogen. For the av...

    Text Solution

    |

  6. One coulomb of charge passes through solutions of AgNO3 and CuSO4. The...

    Text Solution

    |

  7. When electricity is passed through molten AlCl3, 13.5 g. of Al is depo...

    Text Solution

    |

  8. One Faraday charge was passed through the electrolytic cell placed in ...

    Text Solution

    |

  9. The weight in grams of O2 formed at Pt anode during the electrolys of ...

    Text Solution

    |

  10. When one ampere current is passed through a Cu wire for 10 sec., the n...

    Text Solution

    |

  11. How many coulombs of electricity are required for the reduction of 1 m...

    Text Solution

    |

  12. Electric charge on 1gm ion of N^(3-) is

    Text Solution

    |

  13. The charge required for the oxidation of one mole of Mn3O4 " to " MnO...

    Text Solution

    |

  14. Time required to deposit one millimole of aluminium metal by the passa...

    Text Solution

    |

  15. Two electrolytic cells, one containing acidified ferrous sulphate and ...

    Text Solution

    |

  16. On passing a current through a KCl solution, 19.5g of potassium is dep...

    Text Solution

    |

  17. When an electric current is passed through acidulated water, 112 ml of...

    Text Solution

    |

  18. The amount of chlorine evolved when 2 amperes of current is passed for...

    Text Solution

    |

  19. The conductivity of 0.001 M acetic acid is 5 xx 10^(-5) S cm^(-1) and ...

    Text Solution

    |

  20. The distance between two electrodes of a cell is 2.5 cm and area of ea...

    Text Solution

    |