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The E^(@) at 25^(@)C for the following ...

The `E^(@)` at ` 25^(@)C` for the following reaction at the indicated concentrations is 1.50 V . Calculate the `DeltaG ` in kJ at ` 25^(@)C , Cr(s) + 3Ag^(+) (aq. 0.1 M)to Ag(s) + Cr^(3+) (aq. 0.1 M)`

A

`-140.94`

B

`-295`

C

`-212`

D

`-422.83 kJ`

Text Solution

Verified by Experts

The correct Answer is:
D
`Cr_((s)) + 3Ag^(+) aq (0.1 M) to Ag_((s)) + Cr^(+3) aq (0.1) M `
` E_(cell ) =E - (0.059)/(n) log ""([Cr^(+3)])/( [Ag^(+3)]) = E-(0.059)/(3) log_(10)""([Cr^(3+)])/([Ag^(+3)]^(3))`
`= 1.5 - (0.059)/(3) log_(10) ([0.1])/([0.1]^(3)) = 1.5 - 0.039 = 1.4`
` Delta G = -nFE = -3 xx 96,500 xx 1.4 = -422 . 83 KJ`
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