Home
Class 12
CHEMISTRY
The electrochemical cell shown below is ...

The electrochemical cell shown below is a concentration cell.
`M|M^(2+)` (saturated solution of a sparingly soluble salt, `MX_2` || `M^(2+)` (0.001 mol `dm^(-3)`) |M
The emf of the cell depends on the difference in concentration of `M^(2+)` ions at the two electrode The emf of the cell at 298 is 0.059 V
The solubility product `(K_(sp) , mol^(3) dm^(-9)) ` of `MX_2 ` at 298 based on the information available the given concentraiton cell is (take ` 2.303 xx R xx 298 // F = 0.059 V`)

A

` 1 xx 10^(-15)`

B

`4 xx 10^(-15)`

C

`1 xx 10^(-12)`

D

`4 xx 10^(-12)`

Text Solution

Verified by Experts

The correct Answer is:
B
`0.059 = (-0.059)/(2) log ""([M^(+2)])/(10^(-3)) , S = [M^(+2)] M xx 2 = 10^(-2) xx 10^(-3) = 10^(-5)`
` K_(gp) = [M^(+2)] [X^(-)]^(2) = (10^(-5)) (2 xx 10^(-5))^(2) = 4 xx 10^(-15)`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise LEVEL-II (LECTURE SHEET ( EXERCISE -III(MATCH THE FOLLOWING QUESTIONS )))|6 Videos

  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise LEVEL-II (LECTURE SHEET ( EXERCISE -IV (INTEGER ANSWER TYPE QUESTIONS)))|11 Videos

  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise LEVEL-II (LECTURE SHEET ( EXERCISE -I ( SINGLE & ONE OR MORE THAN ONE CORRECT ANSWER )))|32 Videos

  • DILUTE SOLUTIONS

    AAKASH SERIES|Exercise EXERCISE - 1.2|55 Videos

  • ELEMENTS OF D - BLOCK

    AAKASH SERIES|Exercise EXERCISE - 5.2|33 Videos

Similar Questions

Explore conceptually related problems

The electrochemical cell shown below is a concentration cell. M|M^(2+) (saturated solution of a sparingly soluble salt, MX_2 || M^(2+) (0.001 mol dm^(-3) ) |M The emf of the cell depends on the difference in concentration of M^(2+) ions at the two electrode The emf of the cell at 298 is 0.059 V The value of DeltaG (kJ " mol"^(-1)) for the given cell is ( take 1F = 96500 C " mol"^(-1) )

For the cell Zn// Zn^(2+) // // Cu^(2+) // Cu , if the concentration of Zn^(2+) and Cu^(2+) ions is doubled , the emf of the cell

If the solubility product of MOH is 1xx 10^(-10) mol^(2) dm ^(-2) Then the P^(H) of its aqueous solutions will be

If the solubility product of MOH is 1xx10^(-10) mol^(2).dm^(-2) . Then the p^(H) of the its aqueous solution will be

K_(sp) of a salt , having the general formula MX_2 in water 4xx10^(-12) The concentration of M^(2+) ions in the aqueous solution of the salt is

What is the concentration of CN^(-) ions in a solution with 0.1 M HCl and 0.01 M HCN where K_a of HCN is 10 ^(-6) ?

12 cells of each e.m.f 2V are connected in series among them, if 3 cells are connected wrongly. Then the effective e.m.f. of the combination is