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The ratio of ((Lambda(m))/(Lambda(c))) f...

The ratio of `((Lambda_(m))/(Lambda_(c)))` for `Ca_(3)(PO_4)_2` will be equal to ...........

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The correct Answer is:
6
`(^^_n)/(^^_e)=" valence factor " = 6 , Ca_3 (PO_4)_2 , 3Ca^(+2) = 3 xx 2 =6`
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