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At what pH the oxidation potential of hy...

At what pH the oxidation potential of hydrogen electrode will be -0.413 V ?

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The correct Answer is:
7
`E = (-0.0591)/(1) log""(1)/([H^(oplus)]), (-(E xx 1)/(0.0591)) = - log(H^(oplus)) = P^(H) , P^(H) = 6.988 ~= 7`
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