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What is the equivalent weight of O2 in t...

What is the equivalent weight of `O_2` in the following reaction, `H_2O + (1)/(2)O_2 + 2e^(-) to 2OH^(-)`?

Text Solution

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The correct Answer is:
8
`underset((g))(O_2) + underset((l))(2H_2O) +4e^(-) to underset((aq))(4OH^(-))` valency =4
Equivalent weight of `O_2 = ("Molecular weight of "O_2)/("valency")=(32)/(4) = 8`
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