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The equilibrium constant of the reaction...

The equilibrium constant of the reaction
`Cu_((s)) + 2Ag_((aq))^(+) iff Cu_((aq))^(+2) + 2Ag_((s)) , " is " x xx 10^(15) , 'x'` is (`E^(@) = 0.46 V ` at 298 K )

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The correct Answer is:
4
`E^(0) = (0.0591)/(2) log K_(e) , log K_(e) = (0.46 xx 2)/(0.0591) = 15 . 567 , K_(e) = 10^(15) xx 4 `
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