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The charge required for the reduction of...

The charge required for the reduction of 0.4 mol of `K_2Cr_2O_7` to ` Cr^(3+)` ions is

A

0.6 F

B

` 2.4 xx 96500 C `

C

`6 xx 96500 C `

D

` 12.4 xx 96500 F `

Text Solution

Verified by Experts

The correct Answer is:
B
`K_2Cr_2 O_7 to Cr^(+3) ,` For 1 mole ` to 6 xx 96500 c `, 0.4 mole ` to?`
`(0.4 xx 6 xx 96500)/(1) = 2.4 xx 96500`
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