Consider the cell Ag | AgBr | KBr || KCl...

Consider the cell `Ag | AgBr | KBr || KCl | AgCl | Ag` with EMF 0.059 V . Assume that `[Br^(-)] = [Cl^(-)]` . Here , conclusion inferred may be

The ratio of the simultaneous solubilities of AgCl and AgBr in pure water is 1000

It is concentration cell

Change in concentration of KCl will not effect EMF

`K_(sp) (AgCl) gt K_(sp) (AgBr)`

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The correct Answer is:

B, D

`E_(RP) = E_(SRP)^(0) -(0.0591)/(1) log""((Ag^(Ɵ))_a)/((Ag^(oplus))_e) ,0.059 = 0-(0.0591)/(1) log ""(K_(sp) AgBr[Br^(-)])/(K_(sp)AgCl[Cl^(-)]) = 10^(-1)`
` (K_(sp)AgBr)/([Br^(Ɵ)]) xx 10 = (K_(sp) AgCl)/([Cl^(Ɵ)]), K_(SP) [Br^(Ɵ)] = [Cl^(Ɵ)] ` Then ` K_(sp) AgCl to K_(sp) AgBr`

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