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10^(-2)F charge can remove entrie Cl2 fr...

`10^(-2)F` charge can remove entrie `Cl_2` from 100 ml of HCl solution. What is the `P^(H)` of the solution initially

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The correct Answer is:
1
`1F to ` remove 1 mole ` Cl^(Ɵ)` to ` (1)/(2)Cl_2 , 10^(-2) F to ` remove ` 10^(-2)` mole `Cl^(Ɵ)` to `((10^(-2))/(2))Cl_2`
`(H^(oplus)) = [HCl]=(n)/(v) = (10^(-2) " mole")/((100//1000)) = 10^(-2) xx 10 = 10^(-1) , P^(H) =1`
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