Home
Class 12
CHEMISTRY
How many faradays of charge is consumed ...

How many faradays of charge is consumed during electrolysis of acidified water producing 33.6lt of gases at both electrodes .

Text Solution

Verified by Experts

The correct Answer is:
2

`H_2O overset("electrolysis/2F")to H_2 + (1)/(2) O_2 , 2F to (3)/(2)` mole of gases
` 2F to (3)/(2) xx 22.4L , Q to 33.6 , Q = (33.6 xx 2F xx 2)/(22.4 xx 3) = 2F = 2F`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise PRACTICE SHEET -5 (SINGLE OR MORE THAN ONE OPTION QUESTIONS)|16 Videos
  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise PRACTICE SHEET -5 (LINKED COMPREHENSION TYPE QUESTIONS (PASSAGE-I))|3 Videos
  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise PRACTICE SHEET -4 (MATCH THE FOLLOWING QUESTIONS)|2 Videos
  • DILUTE SOLUTIONS

    AAKASH SERIES|Exercise EXERCISE - 1.2|55 Videos
  • ELEMENTS OF D - BLOCK

    AAKASH SERIES|Exercise EXERCISE - 5.2|33 Videos

Similar Questions

Explore conceptually related problems

How many faradays of charge is transfered during disproportionation of two moles of cuprous ?

Electrolysis is the process in which electrical energy is converted to chemical energy. In electrolyte cell, oxidation takes place at anode and reduction at cathode. Electrode process depends on the electrode taken for electrolysis. Amount of substance liberated at an electrode is directly proportionation to the amount of charge passed through it. The mass of substance liberated at electrode is calculate using the following realation : m=(itE)/(96500) Here, E represent the equivalent mass and 96500 C is called the faraday constant. Faraday (96500 C) is the charge of 1 mole electron i.e., 6.023 xx 10^(23) electrons, it is used to liberate on gram equivalent of the substance. The platinum electrodes were immersed in a solution of cupric sulphate (CuSO_4) and electric current is passed through the solution. After sometimes, it was observed that the colour of copper sulphate disappeared with evolution of a gas at the electrode. The colourless solution contains.

Oxygen and hydrogen gases are produced at the anode and cathode during the electrolysis of fairly concentrate aqueous solution of :

Four moles of electrons were transferred from anode to cathode in an experiment on electrolysis of water. The total volume of the two gases (dry and at STP) produced will be approximately (in litres)

During electrolysis of one mole or aq HCOOK . How many moles of H_2 is formed overall ?

How many grams of sucrose should be dissolved in 100g water in order to produce a solution having difference between the free zing point and the boiling point temperatures at 105.0^@C

Electrolysis involves electronation and de-electronation at the respective electodes. Anode electrolytic cell is the electode at which de-electronation takes place whereas at cathod electronation is noticed. If two or more ions of same charge are to be electonated or deelectronate the ion having lasser discharge potential is discharged. Discharge potential of anion refers for EP_(OP)^(@) of E_("RP")^(@) as the case may be. The products formed at either electode is given in terms Faraday's laws of electrolusis i.e. w=(Eit)/(96500) During electrolysis of CuSO_(4(aq)) , the pH of solution becomes

Electrolysis is the process in which electrical energy is converted to chemical energy. In electrolyte cell, oxidation takes place at anode and reduction at cathode. Electrode process depends on the electrode taken for electrolysis. Amount of substance liberated at an electrode is directly proportionation to the amount of charge passed through it. The mass of substance liberated at electrode is calculate using the following realation : m=(itE)/(96500) Here, E represent the equivalent mass and 96500 C is called the faraday constant. Faraday (96500 C) is the charge of 1 mole electron i.e., 6.023 xx 10^(23) electrons, it is used to liberate on gram equivalent of the substance. The passage of current liberates H_2 at cathode and Cl_2 at anode. The solution is

Electrolysis is the process in which electrical energy is converted to chemical energy. In electrolyte cell, oxidation takes place at anode and reduction at cathode. Electrode process depends on the electrode taken for electrolysis. Amount of substance liberated at an electrode is directly proportionation to the amount of charge passed through it. The mass of substance liberated at electrode is calculate using the following realation : m=(itE)/(96500) Here, E represent the equivalent mass and 96500 C is called the faraday constant. Faraday (96500 C) is the charge of 1 mole electron i.e., 6.023 xx 10^(23) electrons, it is used to liberate on gram equivalent of the substance. Calculate the volume of gas liberated at the anode at STP during the electrolysis of a CuSO_4 solution by a current of 1 A passed for 16 minutes and 5 seconds.