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lambda(HCN) is 0.1 M solution is 20S m...

`lambda_(HCN)` is 0.1 M solution is ` 20S m^(2) " mol"^(-1)`
` lambda_(HCN)^(@) ` is 200S `m^(2) "mol"^(-1)` . The `P^(H)` of 0.1M HCN solution is ____________

Text Solution

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The correct Answer is:
2
`alpha = (^^_(HCN))/(^^_(HCN)^(0)) = (20)/(200) = 10^(-1) , [H^(oplus)] = C alpha = 0.1 xx 10^(-1) = 10^(-2) , P^(H) =2 `
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