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Cdo has NaCl structure with density 8.27...

Cdo has NaCl structure with density 8.27 g/cc. If the ionic radius of `O^(2-)` is `1.24 Å`, determine ionic radius of `Cd^(2+)`

A

`1.5Å`

B

`1.1Å`

C

`1.9Å`

D

`1.5Å`

Text Solution

Verified by Experts

The correct Answer is:
B
`d =(Zm)/(a^(3)N), 8.27 =(4 xx 128)/(a^(3) xx 6 xx 10^(23)) rArr a = 4.68 A^(0) = 2[r^(+) + r^(-)], r_(Cd^(+2)) =1.1 A^(0)`
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