Density of a unit cell is represented as
`rho=("Effectiveno.ofatom(s)x Mass of a unit cell")/("Volume of a unit cell")=(Z.M.)/(N_(A).a^(3))`
Where, mass of unit cell = mass of effective no. of atom(s) or ion(s).
M = At. wt./formula wt.
`N_(A)="Avogadro’s no. "rArr 6.023xx10^(23)`
a = edge length of unit cell 
Silver crystallizes in a foc lattice and has a density of `10.6g//cm^(3)`? What is the length of an edge of the unit cell?

Options

A. 0.407 nm
B. 0.2035 nm
C. 0.101 nm
D. 0.407 nm

Answer

A

Explanation

`d=(Zm)/(a^(3) N) rArr (4 xx 108)/(a^(3) xx 6 xx 10^(23)) = 10.6 = 67.6610^(-24)` (or) 0.407 nm