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1.30 Lit N2 gas at 2atm and 300K in a co...

`1.30 Lit N_2` gas at 2atm and 300K in a container is exposed to 4g of solid surface. After complete adsorption the pressure of `N_2` is reduced by 30% calculate the value of x/m 

A

0.22

B

0.56

C

0.32

D

0.43

Text Solution

Verified by Experts

The correct Answer is:
A
Pressure is reduced by 30% `=(2 xx 30)/(100) 0.6 atm`
`PV = W/(MRT) , 0.6 xx 1.3 = W/28 xx 0.0821 xx 300 , wt = 0.8732 , x/m = (0.8732)/(4) = 0.22`
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