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3.6gr of O2 is adsorbed on 1.2gr of meta...

3.6gr of `O_2` is adsorbed on 1.2gr of metal powder what volume of `O_2` adsorbed per gram of the adsorbent at latm and 273K 

A

2.1

B

0.19

C

1

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
Mass of `O_2` per gram of adsorbent = `(3.6)/(1.2) = 3`
No. of moles of `O_2` pergram of adsorbent = `3/32`
Volume of `O_2` per gram of adsorbent `3/32 xx (0.0821 xx 273)/1 = 2.1`
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