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Number of moles of [NH4OH] required to c...

Number of moles of `[NH_4OH]` required to coagulate 1mole of `[Fe(OH)_3]Fe^(+3)` are 

A

3

B

4

C

2

D

1

Text Solution

Verified by Experts

The correct Answer is:
A

`3NH_4OH + [Fe(OH)_3]Fe^(+3) to Fe(OH)_3`
Moles of `NH_4OH` required to coagulate `[Fe(OH)_] Fe^(+3)` ion = 3
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