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Plot of "log" x/m against log p is a str...

Plot of `"log" x/m` against log p is a straight line inclined at an angle of `45^@`. When the pressure is 0.5atm and k value is 10, the amount of solute adsorbed per gram of adsorbent will be 

A

5gm

B

10gm

C

1gm

D

15gm

Text Solution

Verified by Experts

The correct Answer is:
A
`"log" x/m = log K + 1/n "log P"`
`tan 45^@ , 1/n = 1 , x/m = K.P.^(1/n) , 10 xx 0.5= 5
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