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'X’ moles of N2 gas at S.T.P. conditions...

'X’ moles of `N_2` gas at S.T.P. conditions occupy a volume of 10 litres, then the volume of ‘2x’ moles of `CH_4` at `273^@C` and 1.5 atm is 

A

20 lit

B

26.6 lit

C

5 lit

D

16.6 lit

Text Solution

Verified by Experts

The correct Answer is:
B
x moles at `STP to 10 lit`
`implies 2x` moles of any gas at STP = 20 lit.
`(1 xx 20)/(273) = (1.5 xx V_2)/(546) implies V_2 = 26.67L`.
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