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A certain volume of Methane diffuses in ...

A certain volume of Methane diffuses in 10 Sec through a porous partition. The time taken by an equal volume of oxygen to diffuse under the same condition is 

A

14.14 Sec.

B

7.07 Sec.

C

20 sec.

D

5 Sec

Text Solution

Verified by Experts

`((DeltaV)/(10))/((DeltaV)/(t_2)) = sqrt(32/16) = sqrt(2)`.
`(t_2)/(10) = 1.414 implies t_2 = 14.14 "sec"`.
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