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The rate of effusion of two gases 'a' an...

The rate of effusion of two gases 'a' and 'b' under identical conditions of temperature and pressure are in the ratio of 2:1. What is the ratio of rms velocity of their molecules if `T_a` and `T_b`  are in the ratio of 2:1 

A

`2:1`

B

`sqrt(2)`:1

C

`2sqrt(2):1`

D

`1:sqrt(2)`

Text Solution

Verified by Experts

`(gamma_a)/(gamma_b) = sqrt((M_b)/(M_a)) = 2/1 implies M_b = 4M_a`.
`((U_(rms))_(a))/((U_(rms))_b) = sqrt((T_a )/(T_b xx M_a)) = sqrt((2)/(1) xx 4/1) = 2sqrt(2) :1`.
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