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According to Graham's law at a given tem...

According to Graham's law at a given temp, the ratio of diffusion `r_A//r_B`, of gases A and B is given by 

A

`((P_A)/(P_B))((M_A)/(M_B))^(1/2)`

B

`((M_A)/(M_B))((P_A)/(P_B))^(1/2)`

C

`((P_A)/(P_B))((M_B)/(M_A))^(1/2)`

D

`((M_A)/(M_B))((P_B)/(P_A))^(1/2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`(gamma_A)/(gamma_B) = sqrt((M_B)/(M_A)) xx (P_A)/(P_B)` .
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