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What is the compressibility facto (Z) fo...

What is the compressibility facto (Z) for 0.02 mole of a van der Waal's gas at pressure of 0.1 atm. Assume the size of gas molecules is neligible.
Given : RT = 20 L. atm `"mol^(-1)` and `alpha` = 1000 atm `L^(2) "mol^(-2)`

A

2

B

1

C

0.02

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
D
`[0.1 + (100 + (0.02)^2)/(V^2)] = 20 xx 0.02`
`0.1 V^2 - 0.4 V + 0.4 = 0`.
`= V^2 - 4V + 4 = 0 implies V = 2L`
`Z = (PV)/(nRT) = (0.1 xx 2)/(20 xx 0.02) = 0.5`.
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