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The density of air 380K and 722 mm of Hg...

The density of air 380K and 722 mm of Hg is lg/`cm^3`. If air is cooled to 100K and 1 atm the final density is :

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The correct Answer is:
4
`(P_1)/(d_1T_1) = (P_2)/(d_2T_2) , (722)/(1 xx 380) = (760)/(d_2 xx 100)`.
`implies d_2 = 4 g//cm^3`.
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