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Latent heat of vapourisation of a liquid...

Latent heat of vapourisation of a liquid at 500k and 1atm pressure is 10K. Cal/mole. What is the change in internal energy when 3 moles of the liquid is vapourised at the same temperature

A

27kCal

B

7k Cal

C

33k Cal

D

25k Cal

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta H_(v) = 10` kcal/mole
`Delta U = Delta H- Delta n_(g) RT`
`=3 xx 10 xx 10^(3) - 3 xx 2 xx 500= 27` kcal
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