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Two mole of an ideal gas is heated at co...

Two mole of an ideal gas is heated at constant pressure of one atmosphere from `27^(@)C` to `127^(@)C`. If `C_(v, m) = 20 + 10^(-2) TJK^(-1) mol^(-1)`, then q and `Delta U` for the process are respectively.

A

6362.8J, 4700J

B

1522.2 Cal, 1124.4 Cal

C

7062.8 5400J

D

3181.4J 2350J

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
`Delta u = nC_(v) dT = underset(T_(1))overset(T_(2))int n(20 + 10^(-2)T) dT`
`= 2[20(T_(2) - T_(1)) + 10^(-2) [(T_(2)^(2) - T_(1)^(2))/(2)]]`
`=2 [20 (100) + 10^(-2) [(400)^(2) - (300)^(2))/(2)]]`
= 4700J
Work done `= - P_("ext") (V_(2) - V_(1))`
`= -1 (nT_(2) R)/(P)- (nT_(1)R)/(P)= -nR. Delta T` `4700 = Q- (1662.8) rArr Q= 6363.8 J`
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