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1L of NH(3) " at " 27^(@)C is expanded a...

1L of `NH_(3) " at " 27^(@)C` is expanded adiabatically to x litres and final temperature is `-123^(@)C`. What is the value of x?

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Verified by Experts

The correct Answer is:
8
In adiabatic processs `Tv^(gamma-1)` = constant
So `300.(1)^(1//3) = (150).(x)^((1)/(3)) .x= 8`
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