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For a liquid, enthalpy of fusion is 1.43...

For a liquid, enthalpy of fusion is `1.435 xx 10^(3) cal mol^(-1)` and molar entropy change is `5.26 cal mol^(-1)`. Calculate the melting point of the liquid.

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The correct Answer is:
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`Delta H_(f) = 1.435 xx 10^(3), Delta S= 5.26`
`Delta S= (Delta H)/(T_(MP))`
`rArr M.P. = (1.435 xx 10^(3))/(5.26) = 273 = 0^(@)C`
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