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Calculate the free energy change in kJ w...

Calculate the free energy change in kJ when 1 mole of NaCl is dissolved in water at 298 K, Given
a) U of NaCl (U = lattice energy) `= 778 kJ "mole"^(-1)`
b) Hydration energy of NaCl `= -774.3 kJ "mole"^(-1)`
(c) Entropy change at 298K = `43 "mole"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
9
`Delta H` of solution of NaCl= Lattice energy of NaCl- Hydration energy of NaCl
`Delta G= Delta H - T Delta S= - 9`
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