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Given C+ 2S rarr CS(2), DeltaHf^(0) = +1...

Given `C+ 2S rarr CS_(2), DeltaHf^(0) = +117.0 KJ mol^(-1), C + O_(2) rarr CO_(2), DeltaHf^(0)= -393.0 KJ mol^(-1) S + O_(2) rarr SO_(2), DeltaHf^(0) = -297.0 KJ mol^(-1)`. The heat of combustion of `CS_(2) + 3O_(2) rarr CO_(2) + 2SO_(2)` is

A

`-807 KJ mol^(-1)`

B

`-1104 KJ mol^(-1)`

C

`+1104 KJ mol^(-1)`

D

`+807 KJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`CS_(2) + 3O_(2) rarr CO_(2) + 2SO_(2)` …(1)
`C + 2S rarr CS_(2)` …(2)
`C + O_(2) rarr CO_(2)` …(3)
`S + O_(2) rarr SO_(2)` …(4)
Eq(1) = - Eq(2) + Eq.(3) + 2 Eq. (4)
`Delta H = -(117.0) + (-393.0) + 2(-297.0)`
`= -104` KJ/mole
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