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NaOH((aq)) + HCl((aq)) rarr NaCl((aq)) +...

`NaOH_((aq)) + HCl_((aq)) rarr NaCl_((aq)) + H_(2)O, Delta H= -13.6` Kcal. `H_(2(g)) + (1)/(2) O_(2(g)) rarr H_(2)O , Delta H = - 68` Kcal. What is hat of formation of `OH^(-)` ?

A

`-54.4` kCal

B

`+54.4` kCal

C

`+13.6` kCal

D

`-13.6` kCal

Text Solution

Verified by Experts

The correct Answer is:
A
`NaOH + HCl rarr NaCl + H_(2)O` can be written as
`OH^(-) + H^(+) rarr H_(2)O, Delta H = -13.6`
`Delta H = Delta H_(f_(H_(2)O)) - Delta H_(f_(OH^(-))) rArr - 13.6 = - 68- Delta H_(f_(OH^(-)))`
`Deta H_(f_(OH^(-))) = -54.4` Kcal
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