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Heat liberated in the neutralisation of ...

Heat liberated in the neutralisation of 500 ml of 1N HCl and 500ml of 1N `NH_(4)OH` is `-1.36` K.Cals. The heat of ionisation of `NH_(4)OH` is

A

10.98 kCals

B

`-12.34` kCals

C

`-10.98` kCals

D

12.34 kCals

Text Solution

Verified by Experts

The correct Answer is:
A
eq. neutralised `= 0.5 xx 1`
`0.5 rarr 1.36`K cal
`1 rarr` ?
`Delta H_("neutralisation") = 1.36 xx 2K` kcal/eq = 2.72 Kcal
`:.` heat of ionisation = 13.7 - 2.72
= 10.98 Kcal/mole
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