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The amount of heat released, when 20 ml ...

The amount of heat released, when 20 ml of 0.5 M NaOH is mixed with 100 mL of 0.1M HCl, is x k cal. The heat of neutralisation is

A

`10x "k Cal mole"^(-1)`

B

`100x "k Cal mole"^(-1)`

C

`-100 x"k Cal mole"^(-1)`

D

`-23.92x "k Cal mole"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C, D
eq. neutralised = 10 m.eq
10 m.eq `rarr` - x kJ
1 eq `rarr` ? kJ
`(-x)/(10 xx 10^(-3)) = - 100x kJ`/mole
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