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Enthalpy of neutralization is defined as...

Enthalpy of neutralization is defined as the enthalpy change when 1 mole of acid/base is completely neutralized by base/acid in dilute solution. For strong acid and strong base neutralization net chemical change is `H_((aq))^(+) + OH_((aq))^(-) rarr H_(2)O_((l)), Delta H_(r )^(0) -= - 55.84 kJ//mol`
Under the same conditions how many mL of 0.1M NaOH and 0.05 M `H_(2)A` (strong diprotic acid) should be mixed for a total volume of 100mL to produce the highest rise in temperature:

A

`25: 75`

B

`50 : 50`

C

`75 : 25`

D

`66.66 : 33.33`

Text Solution

Verified by Experts

The correct Answer is:
B
For highest rise, max. neutralization
`rArr` eq. acid = eq base
`rArr 0.05 xx y xx 2 = 0.1 xx x rArr (x)/(y) = (1)/(1)`
i.e., `x=y rArr 50 : 50`
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