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At 0^(@)C ice and water are in equilibri...

At `0^(@)C` ice and water are in equilibrium and `Delta H= 6.0KJ " then " Delta S` will be

A

`22 JK^(-1) mol^(-1)`

B

`35 JK^(-1) mol^(-1)`

C

`48 JK^(-1) mol^(-1)`

D

`100 JK^(-1) mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta S = (Delta H)/(T) = (6000)/(273) = 22`
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