The value of a cylinder containing initially 10L of an ideal gas at 25 atm and `25^(@)C` is opened to the atmosphere, where the pressure is 760 torr and the temperature is `25^(@)C`. Assuming that the process is isothermal the work in L-atm in the process is:

Options

A. 240 L atm
B. `-240` L atm
C. `+250` L atm
D. `-250` L atm

Answer

B

Explanation

`W= - P_("ext") Delta V`
`n_(1) = (25 xx 10)/(RT), n_(2) = (1 xx 10)/(RT)`
moles lost `= (24 xx 10)/(RT)`
Volume occupied by these moles `=(24 xx 10)/(RT) xx RT = 240L`
`:. V_(2) = 10 + 240= 250L`
`rArr W = -1 xx (250-10) = - 240 L`-atm