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C(2)H(6(g)) + 3.5 O(2(g)) rarr 2CO(2(g))...

`C_(2)H_(6(g)) + 3.5 O_(2(g)) rarr 2CO_(2(g)) + 3H_(2)O_((g))`
`Delta S_("vap") (H_(2)O,l) = x_(1) " cal" K^(-1)` (boiling point is `T_(1)`)
`Delta H_(f) (H_(2)O, l) = x_(2), Delta H_(f) (CO_(2)) = x_(3), Delta H_(f) (C_(2)H_(6)) = x_(4)` Hence `Delta H` for the reaction is

A

`2x_(3) + 3x_(2) - x_(4)`

B

`2x_(3) + 3x_(2) - x_(4) + 3x_(1) T_(1)`

C

`2x_(3) + 3x_(2) - x_(4) - 3x_(1) T_(1)`

D

`x_(1) T_(1) + X_(2) + X_(3) - x_(4)`

Text Solution

Verified by Experts

The correct Answer is:
B
`Delta H_("vap") (H_(2)O) = Delta S xx T_(BP) = x_(1)T_(1)`
`Delta H = 2Delta H_(f_(CO_(2))) - Delta H_(f_(C_(2)H_(6)))`
`2x_(3) + 3(x_(2) + x_(1) T_(1)) - x_(4)`
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