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The normal boiling point of a liquid 'A'...

The normal boiling point of a liquid 'A' is 350K. `DeltaH_("vap")` at normal boiling point is 35 kJ/mole. Pick out the correct statement(s). (Assume `DeltaH_("vap")` to be independent of pressure)

A

`Delta S_("vaporisation") gt 100 J//K` mole at 350K and 0.5 atm

B

`Delta S_("vaporisation") lt 100 J//K` mole at 350K and 0.5 atm

C

`Delta S_("vaporisation") lt 100 J//K` mole at 350K and 2 atm

D

`Delta S_("vaporisation") = 100 J//K` mole at 350K and 2 atm

Text Solution

Verified by Experts

The correct Answer is:
A, C
`Delta S = (Delta H)/(BP) = (35 xx 1000)/(350) = 100J//K` mole at 1 atm if `P darr Delta S uarr`
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